Question

Find the surface area and lateral surface area of a cube whose side is 40cm

Answer 1

Answer:

Edge of cube = 40 cm

Lateral surface area of cube = 4 (side) square

Lateral surface area of cube = 4× 40×40= 6400cm square

Answer 2

Step-by-step explanation:

Question :-

• Find the surface area and lateral surface area of a cube whose side is 40 cm.

To Find :-

• TSA of cube.
• LSA of cube.

Solution :-

Given :

• Side = 40 cm

According to the question,

By using the formula,

${\longrightarrow{\sf TSA\ of\ cube\ =\ 6a^2}}$

Where,

• a = length of the side

Finding TSA of cube :

${\longrightarrow{\sf TSA\ of\ cube\ =\ 6a^2}}$

${\longrightarrow{\sf 6(40)^2}}$

${\longrightarrow{\sf 6(1,600)}}$

${\longrightarrow{\sf 6 \times 1,600}}$

${\longrightarrow{\sf 9,600\ cm^2}}$

∴ Hence, TSA of cube is 9,600 cm².

$\rule{300}{2}$

By using the formula,

${\longrightarrow{\sf LSA\ of\ cube\ =\ 4a^2}}$

Where,

• a = length of the side

Finding LSA of cube :

${\longrightarrow{\sf LSA\ of\ cube\ =\ 4a^2}}$

${\longrightarrow{\sf 4(40)^2}}$

${\longrightarrow{\sf 4(1,600)}}$

${\longrightarrow{\sf 4 \times 1,600}}$

${\longrightarrow{\sf 6,400\ cm^2}}$

∴ Hence, LSA of cube is 6,400 cm².

More To Know :-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$