Question

find the surface area and the diagonal of a cuboid 30cm long 24cm wide and 18 cm high

The ans should be 3384cm²
don't fake answers​

Answer 1

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Given :-

Dimensions of Cuboid

• Length, l = 30 cm
• Breadth, b = 24 cm
• Height, h = 18 cm

To find:-

☆Surface area of Cuboid

☆Diagonal of a Cuboid

Formula used :-

$Surface \: area \: of \: Cuboid = 2 \times (lb \: + bh + hl) \\ </u></p><p><u>[tex]Surface \: area \: of \: Cuboid = 2 \times (lb \: + bh + hl) \\ Diagonal \: of \: a \: Cuboid = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} }$

Solution :-

$Surface \: area \: of \: Cuboid = 2 \times (lb \: + bh + hl) \\ = 2 \times (30 \times 24 + 24 \times 18 + 18 \times 30) \\ = 2 \times (720 + 432 + 540) \\ = 2 \times 1692 \\ = 3384 \: {cm}^{2} \\ </u></p><p><u>[tex]Surface \: area \: of \: Cuboid = 2 \times (lb \: + bh + hl) \\ = 2 \times (30 \times 24 + 24 \times 18 + 18 \times 30) \\ = 2 \times (720 + 432 + 540) \\ = 2 \times 1692 \\ = 3384 \: {cm}^{2} \\ Diagonal \: of \: a \: Cuboid = \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ = \sqrt{ {30}^{2} + {24}^{2} + {18}^{2} } \\ = \sqrt{900 + 576 + 324} \\ = \sqrt{1800} \\ = \sqrt{3 \times 3 \times 2 \times 10 \times 10} \\ = 30 \sqrt{2} \: cm$

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