Question

find the surface area and the diagonal of cuboid 3 m long 4 meter wide and 5 meter high

Answer 1

Surface area of cuboid = 2(lb+bh+lh)

= 2(3*4+4*5+3*5)

= 2(12+20+15)

=2*47 = 94m^2

Diagonal of cuboid = underrootl^2+b^2+h^2 =underroot 9+16+25 = underroot 50 = 5 root 2 m

Answer 2

THANKS FOR THE QUESTION
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T.S.A. OF CUBOID=
$2(lb + bh + lh)$
$= 2(3 \times 4 + 4 \times 5 + 5 \times 3)$
$= 2(12 + 20 + 15)$
$= 94{m}^{2}$
DIAGONAL OF CUBOID=
$\sqrt{ {a}^{2} + {b}^{2} + {c}^{2} }$
$\sqrt{ {3}^{2} + {4}^{2} + {5}^{2} }$
$\sqrt{50}$
$7.071m$
YOU CAN ALSO LEAVE AS YOU GET √50 IF YOU DON'T KNOW IT'S VALUE!!


HOPE IT HELPS

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