Find the surface area and volume of a beach ball of diameter 42 cm. ( π = 22/7)
Answers
Answered by
3
Answer:
5544 cm²
38808 cm³
Step-by-step explanation:
Find the surface area and volume of a beach ball of diameter 42 cm. ( π = 22/7)
Beach ball is in shape of sphere
Surface area of Sphere = 4 π R²
Diameter = 42 cm
Radius = Diameter/2
R = 21 cm π = 22/7
Surface area of Beach Ball = 4 * (22/7) * 21²
= 88 * 21 * 3
= 5544 cm²
Volume area of Sphere = (4/3) π R³
R = 21 cm π = 22/7
Surface area of Beach Ball = (4/3) * (22/7) * 21³
= 88 * 21 * 3 * 7
= 38808 cm³
5544 cm²
38808 cm³
Step-by-step explanation:
Find the surface area and volume of a beach ball of diameter 42 cm. ( π = 22/7)
Beach ball is in shape of sphere
Surface area of Sphere = 4 π R²
Diameter = 42 cm
Radius = Diameter/2
R = 21 cm π = 22/7
Surface area of Beach Ball = 4 * (22/7) * 21²
= 88 * 21 * 3
= 5544 cm²
Volume area of Sphere = (4/3) π R³
R = 21 cm π = 22/7
Surface area of Beach Ball = (4/3) * (22/7) * 21³
= 88 * 21 * 3 * 7
= 38808 cm³
mysticd:
d = 42 cm , r = 21 cm , plz , check and edit , sir
Answered by
9
Answer:
i ) Surface area = 5544 cm²
ii ) Volume = 38808 cm³
Explanation:
It is given that,
Diameter of the beach ball
(d) = 42cm
π = 22/7
Radius (r) = d/2
= 42/2
= 21 cm
Now ,
i ) Surface area of the ball
= 4πr²
= 4×(22/7) × (21)²
= 5544 cm²
ii ) Volume of the ball (V)
= (4/3)πr³
= (4/3)×(22/7)×(21)³
= 38808 cm³
••••
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