Find the surface area and volume of a solid in the form of a right circular cylinder with hemispherical ends if the whole length is 22cm and radius of the cylinder is 3cm (take pi =3.14)
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Step-by-step explanation:
Given Find the surface area and volume of a solid in the form of a right circular cylinder with hemispherical ends if the whole length is 22 cm and radius of the cylinder is 3 cm
- Let r be the radius and h be the height of cylinder.
- So r = 3 cm, h = 22 – 2 (3) = 16 cm
- Volume of solid = volume of cylinder + volume of two hemispheres.
- = πr^2 h + 2(2π/3 r^3)
- = π x 3^2 x 16 + 4π/3 x 3^3
- = 565.71 cm^3
- T. S. A = C.S.A of cylinder + S.A. of two hemisphere.
- = 2πrh + 2(2πr^2)
- = 2πr (h + 2r)
- = 2π x 3 (16 + 6)
- = 6 x 3.14 x 22
- = 414.85 cm^2
Reference link will be
https://brainly.in/question/4487483
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