find the surface area and volume of a solid in the form of a right circular cylinder with hemisphere ends if the whole length is 22 cm and radius of the cylinder is 3 cm
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Given Find the surface area and volume of a solid in the form of a right circular cylinder with hemispherical ends if the whole length is 22 cm and radius of the cylinder is 3 cm
Let r be the radius and h be the height of cylinder.
So r = 3 cm, h = 22 – 2 (3) = 16 cm
Volume of solid = volume of cylinder + volume of two hemispheres.
= πr^2 h + 2(2π/3 r^3)
= π x 3^2 x 16 + 4π/3 x 3^3
= 565.71 cm^3
T. S. A = C.S.A of cylinder + S.A. of two hemisphere.
= 2πrh + 2(2πr^2)
= 2πr (h + 2r)
= 2π x 3 (16 + 6)
= 6 x 3.14 x 22
= 414.85 cm^2
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