find the surface area and volumw of a beach ball of diameter 42cm
Answers
Answered by
8
answer of beach ball question :
for a beach ball,
height =diameter =42
so ,radius will be half of it=21 cm
∴r=21 cm
now,
let us consider π=3.14
so now ,
volume of the beach ball=4/3 π r³
=4/3*3.14*21³
=now,
=4*3.14*3087
=38772.72 cm³
so now,
surface area of beach ball=4 π r²
=4 * 3.14 *441
=4 * 1384.74
=5538.96 cm²
ans : The volume of the beach ball is 38772.72 cm³ and ,surface area of beach ball is 5538.96 cm²
for a beach ball,
height =diameter =42
so ,radius will be half of it=21 cm
∴r=21 cm
now,
let us consider π=3.14
so now ,
volume of the beach ball=4/3 π r³
=4/3*3.14*21³
=now,
=4*3.14*3087
=38772.72 cm³
so now,
surface area of beach ball=4 π r²
=4 * 3.14 *441
=4 * 1384.74
=5538.96 cm²
ans : The volume of the beach ball is 38772.72 cm³ and ,surface area of beach ball is 5538.96 cm²
sai7932:
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Answered by
7
d=42 cm,
then
r=42/2 = 21 cm,
therefore
Surface area of ball = 4πr²,
=4×22/7 × 21 × 21,
= 4×22×3×21,
= 5544 cm²,
volume of the ball=4/3πr³,
=4/3 × 22/7 × 21×21×21,
=4×22×7×3×21,
=38808 cm³
then
r=42/2 = 21 cm,
therefore
Surface area of ball = 4πr²,
=4×22/7 × 21 × 21,
= 4×22×3×21,
= 5544 cm²,
volume of the ball=4/3πr³,
=4/3 × 22/7 × 21×21×21,
=4×22×7×3×21,
=38808 cm³
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