Question

find the surface area each of the cuboids whose dimensions are given below. (1) length=5cm, breath= 4cm hight =3cm ​

Answer 1

Answer:

l=5cm, b=4cm and h=3cm

surface area of cuboid=2(lb+bh+hl)

=2(5×4+4×3+3×5)

=2(20+12+15)

=2(47)

=94cm^2

Answer 2

Given :

⬤ Length of cuboid = 5 cm.

⬤ Breadth of Cuboid = 4 cm.

⬤ Height of Cuboid = 3 cm.

To Find :

⬤ Surface Area of Cuboid .

Formula Used :

$\sf[\:{Surface\:Area\:of\:Cuboid=2(lb+bh+hl)}\:]$

Solution :

2 (5×4 + 4×3 + 3×5)

2 (20 + 12 + 15)

2 (47)

94

Therefore , The Surface Area of Cuboid is 94 cm² .

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⬤ Surface Area of Cuboid = 2(lb + bh + hl)

⬤ Volume of Cuboid = l × b × h

⬤ Surface Area of Cube = 4b² (Here b represents Side)

⬤ Volume of Cube = b³

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