find the surface area of a box whose Length breadth and height are 5 metre 10 cm and 700 CM respectively
Answers
Answered by
3
Hii friend,
Length of the box = 5 m = 5×100 = 500 cm
breadth of the box = 10 cm
height of the box = 700 cm.
Surface area of the box = 2(LB+BH+LH)
= 2(500×10+10×700+500×700)
= 2(500+7000+3500)
= 2 × 15500 = 31000 cm².
HENCE,
THE TSA OF BOX = 31000 CM².
HOPE IT WILL HELP YOU.... :-)
Length of the box = 5 m = 5×100 = 500 cm
breadth of the box = 10 cm
height of the box = 700 cm.
Surface area of the box = 2(LB+BH+LH)
= 2(500×10+10×700+500×700)
= 2(500+7000+3500)
= 2 × 15500 = 31000 cm².
HENCE,
THE TSA OF BOX = 31000 CM².
HOPE IT WILL HELP YOU.... :-)
Similar questions