Question

find the surface area of a box whose lenth 40cm breath 27cm hight 10cm​

Answer 1

Answer: 5500cm2

Step-by-step explanation:

By surface area I’m assuming it to be total surface area, so,

TSA of a cuboid=2(lb+bh+hl)

=2[(40)(27)+(27)(10)+(10)(40)]

On calculating, we get,

5500cm2

Answer 2

$\large{ \underline{ \underline{ \bold{ \: Answer : \: \: \: }}}}$

$\to$ Total surface area = 3520 cm²

$\large{ \underline{ \underline{ \bold{ \: Explaination : \: \: \: }}}}$

Length = 40 cm

Breadth = 27 cm

Height = 10 cm

$\huge{ \star}$ The shape of box is cuboidal , Therefore ,

$\to$ TSA = 2(lb + bh + hl)

$\to$ TSA = 2(40 × 27 + 27 × 10 + 10 × 40)

$\to$ TSA = 2(1080 + 270 + 400)

$\to$ TSA = 2(1750)

$\to$ TSA = 3520 cm²

Hence , TSA of box is 3520 cm²