Question

find the surface area of a chalk box which is in the form of a cube having edge 10.5 CM

Answer 1

Answer:

T.S.A = 661.5

L.S.A = 441

Step-by-step explanation:

Lateral surface area of cube = $4a^2$

Where a is the side of the cube

Lateral surface area of cube = 4(10.5)(10.5) = 441

Total surface area of cube = $6a^2$

Where a is the side of the cube

Total surface area of cube = 6(10.5)(10.5) = 661.5

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