Question

find the surface area of a chalk box whose Length breadth and height are 16 cm 8 cm and 6 CM respectively​

Answer 1

Answer:

Tsa=2(Ib +bh+Ih)

= 2(16x8+8x6 +16x6).

=2(128 +48+96) = 2x272 = 544

Tsa=544cm2. Ans

Answer 2

GIVEN :-

• Length Of Chalk Box (L) = 16cm.
• Breadth Of Chalk Box (B) = 8cm.
• Height Of Chalk Box (H) = 6cm.

TO FIND :-

• Surface Area Of Chalk Box.

SOLUTION :-

Formula Of T.S.A Of Cuboid :- 2(LB + BH + HL).

➭ 2(16 × 8 + 8 × 6 + 16 × 6).

➭ 2(128 + 48 + 96).

➭ 2(272)

➭ 544 cm²

Therefore, T.S.A Of Chalk Box = 544cm².