Question

Find the surface area of a chalk box whose length, breadth and height are 16 cm, 8 cm and 6 cm, respectively​...steps required​

Answer 1

Answer:

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Answer 2

Given:

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• Length of the chalk box = 16 cm
• Breadth of the chalk box = 8 cm
• Height of the chalk box = 6 cm

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To find:

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Surface area of the chalk box

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Solution:

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We know that,

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Surface area of a cuboid is 2(lb + bh + lh)

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= 2(16 × 8 + 8 × 6 + 16 × 6) cm$^{2}$

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= 2(128 + 48 + 96) cm$^{2}$

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= 544 cm$^{2}$

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Thus, surface area of the chalk is 544 cm$^{2}$.

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More formulas:

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For cuboid:

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• Total surface area of the cuboid = 2(lb + bh + lh)
• Lateral surface area of the cuboid = 2(l + b)h
• Diagonal of the cuboid
• $= \sqrt{l {}^{2} + b {}^{2} + h {}^{2} }$
• Length of all 12 edges of the cuboid = 4(l + b + h)

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For cube:

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• Total surface area of the cube = 6l$^{2}$
• Lateral surface area of the cube = 4l$^{2}$
• Diagonal of the cube
• $= \sqrt{3} \: l$
• Length of all 12 edges of the cube = 12 l