Question

Find the surface area of a chalk box, whose length, breadth, and height are 18cm, 10cm, and 8cm respectively. ​

Answer 1

Step-by-step explanation:

$\huge\fbox\pink{A}\fbox\blue{N}\fbox\purple{S}\fbox\green{W}\fbox\red{E}\fbox\orange{R}$

lenght (l) = 18 cm.

breadth (b) = 10cm .

height (h) = 8cm .

Formula = 2 ( lb + bh + lh )

☆ Total surface area = 2 ( 18*10 + 10*8 + 8*18) = 2 ( 180 + 80 + 144) = 2 ( 404) = 808cm² . Ans

HOPE IT CAN HELP U ✔

Answer 2

Given

• Length of a chalk box = 18cm
• Breadth of a chalk box = 10cm
• Height of a chalk box = 8cm

⠀

To find

• Surface area of the chalk box.

⠀

Solution

• As we know that chalk box is in the shape of cuboid. We have all dimensions of the cuboid.

⠀

$\: \: \: \: \: \: \: \: \: \:\underline{\sf{\red{We\: know\: that}}}$

⠀

${\dag}\:{\underline{\boxed{\sf{\purple{TSA_{(Cuboid)} = 2(lb + bh + hl)}}}}}$

⠀

• Putting the values

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {TSA = 2(18 \times 10 + 10 \times 8 + 8 \times 18)}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {TSA = 2(180 + 80 + 144)}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {TSA = 2 \times 404}$

⠀

$\frak:\implies\: \: \: \: \: \: \: \: {TSA = 808\: cm^2}$

⠀

Hence,

• Total surface area of the chalk box is 808cm².