Find the surface area of a closed cuboid in water tank of dimension 3.5 m x 1.12 m into 2.09 m
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____Here's your Answer__________
Given;
The Dimensions are 3.5 × 1.12 × 2.09
=> Length = 3.5m
=> Breadth = 1.12m
=> Height = 2.09m.
Therefore,
Total Surface Area of Cuboid = 2( lb + bh + hl)
=> 2 ( 3.5× 1.12 + 1.12 × 2.09 + 2.09 × 3.5)
=> 2 ( 3.92 + 2.34 + 7.31)
=> 2 × 13.57
=> 27.15 m^2.
✔✔✔
____Here's your Answer__________
Given;
The Dimensions are 3.5 × 1.12 × 2.09
=> Length = 3.5m
=> Breadth = 1.12m
=> Height = 2.09m.
Therefore,
Total Surface Area of Cuboid = 2( lb + bh + hl)
=> 2 ( 3.5× 1.12 + 1.12 × 2.09 + 2.09 × 3.5)
=> 2 ( 3.92 + 2.34 + 7.31)
=> 2 × 13.57
=> 27.15 m^2.
✔✔✔
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