Question

Find the surface area of a closed cuboid in water tank of dimension 3.5 m x 1.12 m into 2.09 m

Answer 1

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____Here's your Answer__________

Given;

The Dimensions are 3.5 × 1.12 × 2.09

=> Length = 3.5m

=> Breadth = 1.12m

=> Height = 2.09m.

Therefore,

Total Surface Area of Cuboid = 2( lb + bh + hl)

=> 2 ( 3.5× 1.12 + 1.12 × 2.09 + 2.09 × 3.5)

=> 2 ( 3.92 + 2.34 + 7.31)

=> 2 × 13.57

=> 27.15 m^2.
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