Question

find the surface area of a closed cylinder of radius of 7 cm and height 11 cm

Answer 1

$\Large{\underbrace{\sf{\red{Required\:Solution:}}}}$

Given thαt,

• The rαdius αnd height of α closed cylinder is 7cm αnd 11cm.

◾️We need to find the surfαce αreα of the cylinder.

___________

$\large\star{\boxed{\sf{\red{ Total\:Surface\:Area_{(cylinder)} = 2\pi r(r+h)}}}}$

• Substitute the vαlues αnd simplify.

$\longrightarrow{\sf{ 2\times \dfrac{22}{7} \times 7(7+11)}}$

$\longrightarrow{\sf{ 2\times \dfrac{22}{\cancel{7}} \times \cancel{7}(7+11)}}$

$\longrightarrow{\sf{ 2\times 22\times 18}}$

$\large\implies{\boxed{\sf{\red{ 792 cm^{2}}}}}$

Therefore, the surfαce αreα of the closed cylinder is 792cm².

And we αre done! :D

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Answer 2

$\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$

$\:\:$

$\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$

$\:\:$

• Radius of cylinder is 7 cm

• Height of cylinder is 11 cm

$\:\:$

$\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$

$\:\:$

• Surface area

$\:\:$

$\sf\large\bold{\orange{\underline{\blue{ Solution :-}}}}$

$\:\:$

$\underline{\bold{\texttt{Total surface area of cylinder :}}}$

$\:\:$

➠ 2πr(h + r) ⚊⚊⚊⚊ ⓵

$\:\:$

Where ,

$\:\:$

• r = Radius

• h = Height

$\:\:$

$\underline{\bold{\texttt{Total surface area of given cylinder :}}}$

$\:\:$

• r = 7

• h = 11

$\:\:$

⟮ Putting the above values in ⓵ ⟯

$\:\:$

➜ 2πr(h + r)

$\:\:$

➜ $\sf 2 \times \dfrac { 22 } { 7 } \times 7 (11 + 7)$

$\:\:$

➜ 44 × 18

$\:\:$

➨ 792 sq. cm.

$\:\:$

• Hence the total surface area of cylinder is 792 sq. cm.