find the surface area of a cube whose volume is 512 m3
Answers
Answered by
8
Volume = a³ = 512m³
= a = 8m
thus, surface area of cube = 6a² = 6(8)²
= 384m²
= a = 8m
thus, surface area of cube = 6a² = 6(8)²
= 384m²
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Answered by
5
As it is given,
volume of cube = 512
a³ = 512
a = 8 m
we know that,
surface area of cube= 6a²
= 6(8)²
= 6×64 = 384 m²
volume of cube = 512
a³ = 512
a = 8 m
we know that,
surface area of cube= 6a²
= 6(8)²
= 6×64 = 384 m²
hope it works for you
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