Find the surface area of a cube whose volume is 512 m3.
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1)let the edge of a cube =a m
volume (v)= 512 m3
a^3 = (8m)^3
a= 8 m
2)
lateral surface area = 4a^2
= 4* 8^2
= 4*64
= 256 m2
total surface area = 6a2
= 6* 8^2
= 6* 64
= 384 m^2
volume (v)= 512 m3
a^3 = (8m)^3
a= 8 m
2)
lateral surface area = 4a^2
= 4* 8^2
= 4*64
= 256 m2
total surface area = 6a2
= 6* 8^2
= 6* 64
= 384 m^2
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