Question

find the surface area of a cube whose volume is 729m

Answer 1

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Answer 2

Answer:

The surface area of the given cube is 486 sq.cm.

Step-by-step explanation:

Volume of cube = $Side^3$

Since we are given that the volume of cube =$729 cm^3$

So,  $729=Side^3$

$\sqrt[3]{729} =Side$

$9 =Side$

Thus the side of the given cube is 9 cm

Total Surface area of cube = $6x^2$

Where x is the side

So, Total Surface area of cube = $6(9)^2$

                                                   = $486 cm^2$

Hence the surface area of the given cube is 486 sq.cm.