find the surface area of a cuboid whose(a) length 20th, breadth 15, height 4cm(b) length 16m, breadth 8m,height 6m.
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Step-by-step explanation:
Given that l=20cm, b=12cm, h=9cm
∴T.S.A=2(lb+bh+lh)
=2[(20×12)+(12×9)+(20×9)]
=2(240+108+180)
=2×528
∴T.S.A=1056cm2
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