Question

find the surface area of a cuboid whose(a) length 20th, breadth 15, height 4cm(b) length 16m, breadth 8m,height 6m.I ​

Answer 1

Answer a):

1056cm2

Step-by-step explanation a):  

l=20cm, b=12cm, h=9cm

∴T.S.A=2(lb+bh+lh)

=2[(20×12)+(12×9)+(20×9)]

  =2(240+108+180)

  =2×528

 ∴T.S.A= 1056cm2

I hope it is helpful for you please mark me brilliant

Answer 2

ANs: 1056cm²

STEP BY STEP EXPLANATION:

L = 20cm, B = 12cm, H = 9cm

Therefore, T.S.A = 2(lb + bh + lh)

= 2[( 20 ✖ 12) + ( 12 ✖ 9) + (20 ✖ 9)]

= 2( 240 + 108 + 180)

= 2( 528)

= 1056cm²

Hope it help u..☺