Question

Find the surface area of a cuboid whose dimensions are
4m, 3 m and 2m respectively.

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answer step by step​

Answer 1

Given:-

• Length of Cuboid ,L = 4m
• Breadth of Cuboid,B = 3m
• Height of Cuboid,H = 2m

To Find:-

• Surface area (Total Surface Area).

Solution:-

According to the Question

It is given that ,

The dimensions of Cuboid are 4m , 3m & 2m respectively.

We have to calculate the surface area of the cuboid .

• Surface Area = 2(LB +BH+LH)

where,

• L denote Length
• B denote Breadth
• H denote Height

Substitute the value we get

$\longrightarrow$ Surface Area = 2(4*3+3*2+2*4)

$\longrightarrow$ Surface Area = 2(12+6+8)

$\longrightarrow$ Surface Area = 2(26)

$\longrightarrow$ Surface Area = 52m²

• Hence, the surface area of the Cuboid is 52m².

Answer 2

Answer:

Given :-

• A cuboid whose dimensions are 4 m, 3 m and 2 m respectively.

To Find :-

• What is the surface area of cuboid.

Formula Used :-

$\clubsuit$ Total Surface Area or TSA of Cuboid Formula :

$\mapsto \sf\boxed{\bold{\pink{Total\: Surface\: Area_{(Cuboid)} =\: 2(lb + bh + hl)\: sq.units}}}$

where,

• l = Length
• b = Breadth
• h = Height

Solution :-

Given :

$\bigstar\: \: \rm{\bold{Length =\: 4\: m}}$

$\bigstar\: \rm{\bold{Breadth =\: 3\: m}}$

$\bigstar\: \: \rm{\bold{Height =\: 2\: m}}$

According to the question by using the formula we get,

$\longrightarrow \sf T.S.A_{(Cuboid)} =\: 2\{(4 \times 3) + (3 \times 2) + (2 \times 4)\}$

$\longrightarrow \sf T.S.A_{(Cuboid)} =\: 2(12 + 6 + 8)$

$\longrightarrow \sf T.S.A_{(Cuboid)} =\: 2(18 + 8)$

$\longrightarrow \sf T.S.A_{(Cuboid)} =\: 2(26)$

$\longrightarrow \sf T.S.A_{(Cuboid)} =\: 2 \times 26$

$\longrightarrow \sf\bold{\red{T.S.A_{(Cuboid)} =\: 52\: m^2}}$

$\therefore$ The surface area of cuboid is 52 m².