find the surface area of a cuboid whose length=2m, breadth=4m, height=5m
Answers
Answered by
3
Answer:
Step-by-step explanation:
l=2m
b=4m
h=5m
- A=2(2×4+4×5+5×2)
- A=2(8+20+10)
- A=2(38)
- A=76
Answered by
3
the surface area of cuboid =2(lb +bh+hl) =2*{(2m*4m)+(4m*5m)+(5m*2m)}
=2*{8m2+20m2+10m2}
=2*{38m2}
=76m2
hence the surface area of cuboid is=76m2
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