Question

Find the surface area of a cuboid with the given dimensions.
(a) Length-8cm, Breadth-5cm, Height-4cm
(b) L-5. 8cm , B-4. 5cm, H=2cm​

Answer 1

Here,

We will use our Surface area formula of cubiod that is :

$\sf \bold{Surface \: area \: of \: cubiod = 2(lb + bh + lh)}$

Where,

• l is length of cuboid.
• b is breadth of cuboid.
• h is height of cuboid.

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(a) Length of cuboid is 8 cm.

Breadth of cuboid is 5 cm.

Height of cuboid is 4 cm.

Put l, b and h in surface area formula :

$\sf \longrightarrow 2 \times \bigg((8 \times 5) + (5 \times 4) + (4 \times 8) \bigg)$

$\sf \longrightarrow 2 \times (40 + 20 + 32)$

$\sf \longrightarrow 80 + 40 + 64$

$\sf \longrightarrow \purple{ \boxed{ \sf \bold{184}} \bigstar}$

Therefore,

Surface area of cuboid is 184 cm².

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(b) Length of cuboid is 5.8 cm.

Breadth of cuboid is 4.5 cm.

Height of cuboid is 2 cm.

Put, l, b and h surface area formula :

$\sf \longrightarrow 2 \times \bigg((5.8 \times 4.5) + (4.5 \times 2) + (2 \times 5.8) \bigg)$

$\sf \longrightarrow 2 \times (26.1 + 9 + 11.6)$

$\sf \longrightarrow 52.2 + 18 + 23.2$

$\sf \longrightarrow \red{ \boxed{ \sf \bold{93.4}} \bigstar}$

Therefore,

Surface area of cuboid is 93.4 cm².

Answer 2

Answer:

(a) 184 cm²

(b) 93.4 cm²

Step-by-step explanation:

$\text{\large\underline{\green{Given:}}}$

(a) l = 8 cm, b = 5 cm, h = 4 cm

(b) l = 5.8 cm, b = 4.5 cm, h = 2 cm

$\text{\large\underline{\purple{To\:find:}}}$

• Surface area = ?

$\text{\large\underline{\orange{Solution:}}}$

We know, $\blue{\sf{Surface\:area\:of\:cuboid\:=\:2(lb\:+\:bh\:+\:hl)}}$

(a) Surface area = 2(8 × 5 + 5 × 4 + 4 × 8)

$\longrightarrow$ 2(40 + 20 + 32)

$\longrightarrow$ 2(92)

$\longrightarrow$ 184 cm²

${\large{\boxed{\sf{\therefore \:Surface\:area\:is\:184\:cm^2}}}}$

(b) Surface area = 2(5.8 × 4.5 + 4.5 × 2 + 2 × 5.8)

$\longrightarrow$ 2(26.1 + 9 + 11.6)

$\longrightarrow$ 2(46.7)

$\longrightarrow$ 93.4 cm²

${\large{\boxed{\sf{\therefore \:Surface\:area\:is\:93.4\:cm^2}}}}$