Question

Find the surface area of a cuboid with the given dimensions.
(a) Length-8cm, Breadth-5cm, Height-4cm
(b) L-5. 8cm , B-4. 5cm, H=2cm​

Answer 1

Answer:

(1) length =12 cm breadth =10 cm height =5 cm

TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]

TSA=2[120+50+60]=2×230

[TSA=460cm

2

]

(2) length =5 cm breadth =3.5 cm height =1.4 cm

TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]

TSA=2[17.5+4.90+7.0]=2[29.4]

[TSA=58.8cm

2

]

(3) length =2.5 cm breadth =2 m height =2.4 m

TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]

TSA=2[0.05+4.8+0.0600]=2[4.91]

(4) length =8 m breadth =5 m height =3.5 m

TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]

TSA=2[40+17.5+28.0]=2[85.5]

[TSA=171.0m

2

]

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Answer 2

$\huge\underline{\bf \orange{Aηsωeя :}}$

(a) Surface area = 2(8 × 5 + 5 × 4 + 4 × 8)

⟶ 2(40 + 20 + 32)

⟶ 2(92)

⟶ 184 cm²

∴ Surface area is 184cm²

(b) Surface area = 2(5.8 × 4.5 + 4.5 × 2 + 2 × 5.8)

⟶ 2(26.1 + 9 + 11.6)

⟶ 2(46.7)

⟶ 93.4 cm²

∴ Surface area is 93.4cm²