Find the surface area of a cylinder whose base radius is 14 cm height is 28cm.
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13
Given:-
- Base radius of a cylinder = 14 cm
- Height of a cylinder = 28 cm
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To find:-
- Surface area of a cylinder.
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Solution:-
Here,
- Radius (r) = 14 cm
- Height (h) = 28 cm
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☆Surface area = 2πr(r + h)
⇛ 2 × 22/7 × 14(14 + 28)
⇛ 2 × 22 × 2 × 42
⇛ 3696 cm²
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Hence,
- the surface area of a cylinder is 3696 cm².
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★More Formulas
- Area of rectangle = length × breadth sq.units
- Perimeter of square = 4 × side units
- Area of square = side × side sq.units
- Perimeter of circle = 2πr units
- Area of circle = πr² sq.units
- Perimeter of parallelogram = 2 × (a + b) units
- Area of parallelogram = base × height sq.units
- Perimeter of rhombus = 4 × side units
- Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units
- Perimeter of equilateral triangle = 3 × side units
- Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units
- Perimeter of trapezoid = (Sum of all sides) units
- Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units
Silky23:
Thank you!!
Answered by
2
Radius = 14cm
Height = 28cm
Surface area of given Cylinder = 2π×14(14+28)
= 2×(22/7)×14×(42)
= (44)×2×42
= 88× 42
= 3696 cm sq.
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