Question

.find the surface area of a piece of metal which is in the form of a parallelogram whose base is 10 cm and height is 6.4 cm

Answer 1

surface area of parallelogram=base*height

10*6.4=64cm2

Answer 2

Answer:

$\red {Area \:of \:a \: parallelogram}\green{=64\:cm^{2}}$

Step-by-step explanation:

$Given \: dimensions \: of \: a \: parallelogram:\\base(b) = 10\:cm , \:Height(h) = 6.4 \:cm$

$\boxed {\pink { Area \:of \:a \: parallelogram (A) =bh }}$

$A = 10\:cm \times 6.4\:cm \\= 64\:cm^{2}$

Therefore.,

$\red {Area \:of \:a \: parallelogram}\green{=64\:cm^{2}}$

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