Question

find the surface area of a room of length 25m, height 15m and width 5m.​

Answer 1

Answer:

l =25m

b=5m

h=15m

Total surface area of rectangle = 2(lb+bh+lh)

= 2(25×5+5×15+25×15)

= 2(125+75+375)

= 2×575

= 1150m^2

Lateral surface area of rectangle = 2(l+b)h

= 2×30×15

= 900m^2