Question

find the surface area of a sphere whose volume is 4851 cm³

Answer 1

this is your answer

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★Radius of sphere - r

$\tt{\rightarrow Volume=\dfrac{4}{3}\pi r^3}$

$\tt{\rightarrow\dfrac{4}{3}\pi r^3=4851}$

$\tt{\rightarrow\dfrac{4}{3}\times\dfrac{22}{7}\times r^3 = 4851}$

$\tt{\rightarrow r^3=(4851\times\dfrac{3}{4}\times\dfrac{7}{22})}$

$\tt{\rightarrow(\dfrac{441\times 21}{8})}$

$\tt{\rightarrow(\dfrac{21}{2})^{3}}$

$\tt{\rightarrow r=\dfrac{21}{2}}$

r = 10.5

★Now

Surface area of sphere = 4πr²

$\tt{\rightarrow 4\times\dfrac{22}{7}\times\dfrac{21}{2}\times\dfrac{21}{2}}$

= 1386 cm²

★Therefore we get :-

★Surface area of sphere is 1386 cm²