Question

find the surface area of a sphere whose volume is 4851cm​

Answer 1

Answer :

$vol. \: of \: sphere \: = \frac{4}{3}\pi {r}^{3}$

$= > 4851 = \frac{4}{3} \times \frac{22}{7} \times {r}^{3}$

$= > 4851 = \frac{88}{21} \times {r}^{3}$

$= > {r}^{3} = 4851 \times \frac{21}{88}$

$= > {r}^{3} = 1157.625$

$= > r = \sqrt[3]{1157.625}$

$= > \: r = 10.5 \: cm$

$surface \:area = 4\pi {r}^{2}$

$surface \: area \: = 4 \times \frac{22}{7} \times 10.5 \times 10.5$

$surface \: area \: = 1385.44 \: {cm}^{2}$

Hope this helps you mate ☺☺