find the surface area of cube whose volume is 19683 cubic m
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Answered by
2
Step-by-step explanation:
volume = s^3
16983= s^3
27^3=s^3
s=27
Answered by
0
VOLUME OF CUBE = l^3
19683. = l^3
SO,l =27m
TSA OF CUBE = 6l^2
= 6×27^2
= 6×27×27
= 4374m^2
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