Question

find the surface area of cuboid open the top whose dimensions are 6 CM 4 cm 2 cm​

Answer 1

Answer:

Total surface area of cuboid =2*(lb +bh+hl)

Let the length be 6 cm

Let the height be 2 cm

Let the breadth be 4 cm

Therefore, TSA=2*{(6*4)+(4*2)+(6*2)}

=2*(24+8+12)

=2*(44)

=88 Sq cm

Answer 2

Total surface area of cuboid =2*(lb +bh+hl)

Let the length be 6 cm

Let the height be 2 cm

Let the breadth be 4 cm

Therefore, TSA=2*{(6*4)+(4*2)+(6*2)}

=2*(24+8+12)

=2*(44)

=88 Sq cm