Question

Find the surface area of cuboid whose dimension are given below :
length - 11/2
breadth - 4 cm
height - 21/2
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Answer 1

Answer:

total surface area of a cuboid of sides a,b,c will be 2*((a*b)+(b*c)+(c*a))

2 is multiplied because opposite side areas will be equal and total side side area is to be added

so the answer will be 2*(((11/2)*4)+(4*(21/2)+((21/2)*11/2)) = 243.5

Answer 2

Answer:

the total surface area of cuboid:

=2× [(l × b) + (b × h) + (h × l)] .

=2× [(l × b) + (b × h) + (h × l)] . = 2× [ (11/2)(4) + (4)(21/2) + (21/2)(11/2)

=2× [(l × b) + (b × h) + (h × l)] . = 2× [ (11/2)(4) + (4)(21/2) + (21/2)(11/2)= 2× [ 22 + 42 + 57.75]

=2× [(l × b) + (b × h) + (h × l)] . = 2× [ (11/2)(4) + (4)(21/2) + (21/2)(11/2)= 2× [ 22 + 42 + 57.75] = 2× [ 121.75]

=2× [(l × b) + (b × h) + (h × l)] . = 2× [ (11/2)(4) + (4)(21/2) + (21/2)(11/2)= 2× [ 22 + 42 + 57.75] = 2× [ 121.75] = 243.5