find the surface area of cuboid whose dimensions are 26,20,12
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Answer:
2(lb* bh*hl)
2*26*20*1 2
12480
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l=26,b=20,h=12
tsa=2(26*20+20*12+12*26)
=2(520+240+312)
=2*1072=2144
lsa=24*46
=1024
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