Question

Find the surface area of cuboid whose dimensions are 3m, 4m and 5m.

Answer 1

Answer:

94 m²

Step-by-step explanation:

TSA of Cuboid = 2(lb+bh+hl)

= 2[3(4)+4(5)+5(3)]

= 2[12+20+15]

= 2[47]

= 94 m²

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Answer 2

Answer:

94 m

$94m ^{2}$

Step-by-step explanation:

let l=3

b=4

h=5.

surface area of cuboid =2(lh+bh+lb)

=2([2×5]+[4×5]+[3×4])

=2(15+20+12)

=2(47)

$94 m^{2}$