Question

find the surface area of sphere whose volume is 4851cm^3 ​

Answer 1

volume of sphere

$\longrightarrow\large\frac{4}{3}πr^{3}$

★ by the formula

$\implies 4851=\frac{4}{3}\frac{22}{7}×r^{3}\\\implies r^{3}=\frac{4851×3×7}{4×22}\\ \implies r^{3}=\frac{101871}{88} \\\implies r= \sqrt\frac{3×3×3×7×7×7×11}{2×2×2×11} \\\implies r=\frac{3×7}{2} \\\implies r= \frac{21}{2}cm$

$\rule{300}2$

★ surface area ★

$\longrightarrow\large\frac{4}{3}πr^{3}$

→ again by the formula,

$\implies 4×\frac{22}{7}×\frac{21×21}{4} \\ \implies 66×21 \\\implies 1386cm^{2}$

$\rule{300}2$

Answer 2

the given answer is right......