Find the surface area of sphere whose volume is 5887.32cm cube
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Edge of the cubical tank = 1.5 m = 150 cm (= a)
So, surface area of the tank = 5 × 150 × 150 cm2
Area of each square tile = side × side = 25 × 25 cm2
So, the number of tiles required = Surface area of tank/Area of each tile = 5 x 150 x 150/25 x 25 =180
Cost of 1 dozen tiles, i.e., cost of 12 tiles = Rs 360
Therefore, cost of one tile = Rs 360/12= Rs 30
So, the cost of 180 tiles = 180 × Rs 30 = Rs 5400
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Answer:
Step-by-step explanation:
4pie r^2=1576.9540
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