Math, asked by srilalithl312, 10 months ago

Find the surface area of the cuboid whose dimensions are length 5 1/2 breadth 4cm height 10 1/2

Answers

Answered by guptabhavesh76
0

Answer:85 cm squared

Step-by-step explanation:

Total surface area of cuboid = 2(lb+bh+lh)

= 2(5 1/2 X 4 + 4 X 10 1/2 + 10 1/2 X 5 1/2)

= 85cm squared

Answered by sunnny40
0

Answer:

T.s.a=2(lb+lh+bh)

=2(51/2*4+51/2*10 1/2+4*10 1/2)

=85

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