Question

find the surface area of the cuboid whose dimensions are length equal 7/2 cm breadth = 4 cm and height equal 21/2 cm.​

Answer 1

Given that l=20cm, b=12cm, h=9cm

∴T.S.A=2(lb+bh+lh)

=2[(20×12)+(12×9)+(20×9)]

=2(240+108+180)

=2×528

∴T.S.A=$\huge\bold\red{1056cm²}$

Answer 2

Answer:-

Given that l=20cm,b=12cm,h=9cm

.

. .T.S.A =2(1b+bh+1h)

= 2[ (20×12) ] +(12×9)+(20×9) ]

= 2(240+108+180)

= 2×528

.

. .T.S.A = 1056cm2

Hope it help uh ☺✌ ࿐