Math, asked by shahadkt123, 1 year ago

Find the surface area of the solid generated by revolving the curve, 8y2 = x(x – 8)2 from x = 2 to x = 5 about the X – axis. Also, sketch the graph of the given curve in 0

Answers

Answered by ms6644236
0

Answer:

Find the surface area of the solid generated by revolving the curve, 8y2 = x(x – 8)2 from x = 2 to x = 5 about the X – axis. Also, sketch the graph of the given curve in 0 < x < 8.

Answered by labdhijain1854
0

Answer:

Step-by-step explanation:

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