find the surface area of triangle x+y=7 !!! explain pls!!!
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To find B
3x−2y=−1 and x+y=3
solving above two equations we get
y=2 and x=1
B=(1,2)
To find C
3x−2y=−1 and x−3y=−9
solving above two equations we get
y=27/6 and x=15/7
C=(
7
15
,
6
27
)
s=
2
perimeteroftriangle
a=AB=
(1−0)
2
+(2−3)
2
=
1+1
=
2
b=BC=
(
7
15
−1)
2
+(
7
26
−2)
2
=
(
7
8
)
2
+(
7
12
)
2
=
7
4
13
c=CA=
(
7
15
−0)
2
+(
7
26
−3)
2
=
(
7
15
)
2
+(
7
5
)
2
=
7
5
10
s=
2
a+b+c
s=
2
2
+
7
4
13
+
7
5
10
s=
14
14
2
+4
13
+5
10
s−a=
14
−7
2
+4
13
+5
10
s−b=
14
14
2
−4
13
+5
10
s−c=
14
14
2
+4
13
−5
10
A=
s(s−a)(s−b)(s−c)
A=
(
14
−7
2
+4
13
+5
10
)(
14
14
2
−4
13
+5
10
)(
14
14
2
+4
13
−5
10
)
Multiplying and solving
A=
7
16
sq unit
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