Question

Find the surface density of electric charge at a place on earths surface where the rate of fall of potential is 2.5 V​

Answer 1

Hey Dear,

◆ Answer -

σ = 2.212×10^-11 C/m²

◆ Explanation -

# Given -

E = 2.5 V

ε0 = 8.85×10^-12 F/m

# Solution -

Surface density of electric charge at earth surface is given by -

σ = ε0.E

Substituting the values -

σ = 8.85×10^-12 × 2.5

σ = 2.212×10^-11 C/m²

Hence, surface charge density at earth surface is 2.212×10^-11 C/m².

Hope this helps you. Thanks for asking..