Question

find the surface of cubiod whose length 6 cm breath 2 cm hegith 3 cm​

Answer 1

Answer:

l= 6cm

b=2cm

h=3cm

the surface area of cuboid = 2 (lb+bh+hl)

the surface area of cuboid= 2 ( 6×2+2×3+3×6)

the surface area of cuboid= 2 (12+6+18)

the surface area of cuboid=2×36

the surface area of cuboid=72

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Answer 2

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$\bf\bigstar{QUESTION}$

Find the surface area of a cuboid whose length 6 cm, breath 2 cm, height is 3 cm​  !

$\bf\bigstar{ANSWER}$

The total surface area (TSA) of a cuboid is the sum of the areas of its 6 faces, which is given by:

TSA = 2 (lb + bh + hl)

Here,

Length = 6 cm

Breadth = 2 cm

Height = 3 cm

As we know that,

TSA = 2 ( lb + bh + hl )

TSA = 2 ( 6 x 2 + 2 x 3 + 3 x 6 )

TSA = 2 ( 12 + 6 + 18 )

TSA = 2 ( 36)

TSA = 72 cm ^ 2

The required answer ,

$\huge{\boxed{\bf{72\:cm^2}}}}}$

Hope this answer can helps !!