find the t.s.a. of a closed cardboard box of length 0.5 m.,breadth 25cm and height 15cm.
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Given, length =0.5m=50cm
Breadth =25cm
Height =15cm
As we know = TSA =2 (lb+bh+lh)
=2(50×25+25×15+15×50)
=2 (1250+375+750)cm
=2(2375) cm
=4750cm^2 =47.5m^2
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Breadth =25cm
Height =15cm
As we know = TSA =2 (lb+bh+lh)
=2(50×25+25×15+15×50)
=2 (1250+375+750)cm
=2(2375) cm
=4750cm^2 =47.5m^2
Hope it helps u..
Pls mark my answer as brainliest.
In case of any doubt pls comment below
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