Math, asked by MUKULthakur, 1 year ago

find the t.s.a. of a closed cardboard box of length 0.5 m.,breadth 25cm and height 15cm.

Answers

Answered by Sanjana0105
1
Given, length =0.5m=50cm
Breadth =25cm
Height =15cm
As we know = TSA =2 (lb+bh+lh)
=2(50×25+25×15+15×50)
=2 (1250+375+750)cm
=2(2375) cm
=4750cm^2 =47.5m^2
Hope it helps u..
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Answered by BrainlyConqueror0901
2

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{T.S.A\:of\:cuboid=4750\:cm}^{2}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{ \underline  \bold{given : }} \\  :  \implies  \text{Length(l) = 50 \: cm} \\  \\ :  \implies  \text{Breadth(b) = 25 \: cm} \\  \\ :  \implies  \text{Height(h) = 15 \: cm} \\  \\  \red{ \underline  \bold{to \: find : }} \\ :   \implies  \text{T.S.A \: of \: cuboid  = ? }

• According to given question :

 \bold{as \: we \: know \: that} \\   : \implies  \text{T.S.A \: of \: cuboid} = 2(lb + bh + hl) \\  \\  : \implies  \text{T.S.A \: of \: cuboid} = 2(50 \times 25+ 25 \times 15 + 15 \times 50) \\  \\ : \implies  \text{T.S.A \: of \: cuboid}  = 2(1250 + 375 + 750) \\  \\ : \implies  \text{T.S.A \: of \: cuboid}  = 2 \times 2375 \\  \\  \green{: \implies  \text{T.S.A \: of \: cuboid = 4750 \:{cm}}^{2} } \\  \\  \purple {\text{some \: formula \: related \: to \: this \: topic}} \\  \pink  {\circ \:  \text{L.S.A\: of \: cuboid = }2(l + b) \times h} \\  \\ \pink  {\circ \:  \text{Volume \: of \: cuboid = }l  \times  b \times h}

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