Question

find the (tan+sec-1/tan-sec+1)1/sec​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$( \frac{tan + sec - 1}{tan - sec + 1} ) \frac{1}{sec} \\ = ( \frac{(tan + sec) - ( {sec}^{2} - {tan}^{2} )}{tan - sec + 1} ) \frac{1}{sec} \\ = \frac{(tan + sec)(1 - sec + tan)}{tan - sec + 1} \times \frac{1}{sec} \\ = (tan + sec) \frac{1}{sec} \\ = ( \frac{sin + 1}{cos} ) \frac{1}{sec} \\ = \frac{1 + sin}{cos \: sec} \\ = 1 + sin$