Question

find the tangent of the angle between the lines whose intercepts on the axes are respectively a,-b and b,-a
please answer it as soon as possible​

Answer 1

Answer:

tanx=3/5 (perpendicular/base)

x-intercept is the base.

Therefore, x-intercept = 5.

Equation of line:

x/5 + y/-3 = 1 (slope intercept form)

Ans: 5y-3x+15=0

tanx=3/5 (perpendicular/base)

x-intercept is the base.

Therefore, x-intercept = 5.

Equation of line:

x/5 + y/-3 = 1 (slope intercept form)

Ans: 5y-3x+15=0