Find the tangent to the curve y = (X-7)/[(X-2) (X-3)] where it cuts the X-axis.
Answers
We have curve y(x − 2)(x − 3) − x + 7 = 0. For intersection point of given curve and x – axis (y = 0), putting y = 0 in equation of the curve, we get – x + 7 = 0 ⇒ x = 7. Therefore, the given curve y(x − 2)(x − 3) − x + 7 = 0 cuts the x – axis at the point (7, 0). Now, given curve is y(x − 2)(x − 3) − x + 7 = 0. Differentiating above equation with respect to x, we get Putting x = 7, y = 0 in above equation, we get Read more on Sarthaks.com - https://www.sarthaks.com/1109268/find-the-equations-of-tangent-and-normal-to-the-curve-y-7-0-at-the-point-where-it-cuts-the-axis
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