Question

Find the temperature at which 88g of co2 occupies volume of 5dm cube at 3.30atm pressure

Answer 1

answer : 100.6K

you should use universal gas equation.

e.g., $\boxed{\bf{PV=nRT}}$

$\quad$ where P denotes pressure, V denotes volume , n denotes number of mole , R denotes universal gas constant and T denotes temperature in Kelvin.

here, P = 3.3 atm , V = 5dm³ = 5L [as we know, 1 dm³ = 1L.]

given weight of CO2 = 88g

molecular weight of CO2 = 44g/mol

so, number of mole, n = 88/44 = 2

now, 3.3 × 5 = 2 × 0.082 × T

or, 16.5 = 0.164T

or, T = 16.5/0.164 = 100.6 K