Find the temperature at which the reaction MgO + C → Mg + CO become spontaneous if ∆H = 490 kJ mol– 1 and ∆S = 198 kJ mol– 1.
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The temperature at which the reaction will take place is 2470K.
- As per the given statement, the undergoing reaction is
- MgO + C → Mg + CO
- Here ∆H = 490 kJ mol– 1
- ∆S = 198 kJ mol– 1.
- In this reaction, ∆H is enthalpy and ∆S is entropy.
- To calculate temperature, the formula is given below.
- The entropy is given by the formula
- ∆S=∆H/T
- T=∆H/∆S
- T=490×1000/198
- T=2470K
Thus, at 2470K the reaction will be feasible.
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