Question

Find the temperature at which the rms speed of nitrogen molecule is 512m/s

Answer 1

Answer :

294.2 K

Steps:

$V = \sqrt{\frac{3RT}{M} }\\512 = \sqrt{\frac{3*8.314*T}{0.028} } M in Kg/mol\\262144 = 890.7 * T\\T = \frac{262144}{890.7}\\ T = 294.2 K$